welll i want to show more than one images plz help
and how can i shopw images of specific catagory i had try this
AND a.cat_id=4
but it is not working Sad
*handsome* use this:
<?php
/**************************************************************************
* *
* 4images - A Web Based Image Gallery Management System *
* ---------------------------------------------------------------- *
* *
* File: random_more_pics.php *
* Copyright: (C) 2002 Jan Sorgalla *
* Email: jan@4homepages.de *
* Web: http://www.4homepages.de *
* Scriptversion: 1.0 for 4images 1.6.1 *
* *
* Never released without support from: Nicky (http://www.nicky.net) *
* *
**************************************************************************
* *
* Dieses Script ist KEINE Freeware. Bitte lesen Sie die Lizenz- *
* bedingungen (http://www.4homepages.de/4images/lizenz.php) für *
* weitere Informationen. *
* --------------------------------------------------------------- *
* This script is NOT freeware! Please read the Copyright Notice *
* (http://www.4homepages.de/4images/lizenz_e.php) for further *
* information. *
* *
*************************************************************************/
// PATH to your 4images Gallery / PFAD zu Ihrer 4images Gallerie
define('ROOT_PATH', './');
include(ROOT_PATH.'config.php');
include(ROOT_PATH.'includes/db_mysql.php');
include(ROOT_PATH.'includes/constants.php');
$site_db = new Db($db_host, $db_user, $db_password, $db_name);
function is_remote($file_name) {
return (preg_match('#^https?\\:\\/\\/[a-z0-9\-]+\.([a-z0-9\-]+\.)?[a-z]+#i', $file_name)) ? 1 : 0;
}
// NUMBER OF THUMBNAILS TO DISPLAY / NUMMER DER GEWÜNSCHTEN THUMBNAILS
$num_images = 4;
$sql = "SELECT a.image_id, a.cat_id, a.image_name, a.image_active, a.image_thumb_file, a.image_comments
FROM (".IMAGES_TABLE." a, ".CATEGORIES_TABLE." b)
WHERE a.image_active=1
AND a.cat_id = b.cat_id
AND b.auth_viewcat=".AUTH_ALL."
AND b.auth_viewimage=".AUTH_ALL."
AND a.cat_id = 4
ORDER BY RAND()
LIMIT $num_images";
$result = $site_db->query($sql);
while ($row = $site_db->fetch_array($result)){
$image_id = $row['image_id'];
$cat_id = $row['cat_id'];
$image_name = $row['image_name'];
$image_comments = $row['image_comments'];
$thumb_src = (is_remote($row['image_thumb_file'])) ? $row['image_thumb_file'] : ROOT_PATH.THUMB_DIR."/".$cat_id."/".$row['image_thumb_file'];
echo "<a href=\"".ROOT_PATH."details.php?image_id=$image_id\"><img src=\"".$thumb_src."\" border=\"0\" alt=\"$image_name\"></a><br>\n";
echo "<b>$image_name</b><br>\n";
echo "Comments: $image_comments<hr>\n";
}
?>
thanks for help..
but is it possible to open image in new window... forexample when visitor click on random image its open in new window
i try to add blank tag but it is not working (givving some errors