Private URL to members profile

[VonHerzen]

Hi CanonInk! Vielen dank!
Greetings from very sunny Madrid.

It works now perfectly with some modifications:
1.- On the .htaccess file I needed to insert this code before

Code: [Select]

RewriteEngine On.
2.- It works without creating a folder called who.
3.- As I have used who.php version 1.1 I did not do the array test.php file and it works.

Hey, your website is nice! Thank you once again!!   

[CanonInk]

Hi CanonInk! Vielen dank!
Greetings from very sunny Madrid.

It works now perfectly with some modifications:
1.- On the .htaccess file I needed to insert this code before

Code: [Select]

RewriteEngine On.
2.- It works without creating a folder called who.
3.- As I have used who.php version 1.1 I did not do the array test.php file and it works.

Hey, your website is nice! Thank you once again!!   

- You are right with step 1
- who needs at my server
- this is possible, but is dependent on server (Apache,...)

Thank you very much for the flowers 

CanonInk

[crs]

Hello

Maybe i click on a User on a page, the following link appears in my browsers url input bar: http://mypage.de/member.php?action=showprofile&user_id=5

Is it possible to show only the private URL in the browsers input-bar?
Im asking for that, because the users didnīt see, that they got a short-url to her own profile and they are using the long links -.-

Thanks for help

[Sunny C.]

Da ich Google Friendly URLs installiert habe, habe ich die who.php so abgewandelt:

<?
// Settings
///////////////////////////////////////////

$url = "http://www.meineseite.de";
$table = "4images_users"; //do not edit if you have not changed table prefix 

// Code
///////////////////////////////////////////

include "config.php";
$a_url = $_SERVER["REQUEST_URI"];
$i = explode("/", $a_url);
$b = count($i);
$b = $b-1;
$i = str_replace(array("%20"), " ", $i[$b]);
if (($i != "") and ($i != "guest"))
{

$db = mysql_connect("$db_host", "$db_user", "$db_password") or die ("Error");

@mysql_select_db("$db_name", $db) or die ("DB not found");

$result = mysql_query("SELECT user_id FROM `$table` WHERE user_name='$i'");

$row = mysql_fetch_array($result);

$id = $row['user_id'];

header("Location: ".$url."/profile".$id.".htm");
}
else
{
header("Location: ".$url."");
}
?>

Das klappt wunderbar. Jetzt wollte ich eine weitere Datei erstellen, namens Image:

image.php
<?
// Settings
///////////////////////////////////////////

$url = "http://www.meineseite.de";
$table = "4images_images"; //do not edit if you have not changed table prefix 

// Code
///////////////////////////////////////////

include "config.php";
$a_url = $_SERVER["REQUEST_URI"];
$i = explode("/", $a_url);
$b = count($i);
$b = $b-1;
$i = str_replace(array("%20"), " ", $i[$b]);
if (($i != "") and ($i != "guest"))
{

$db = mysql_connect("$db_host", "$db_user", "$db_password") or die ("Error");

@mysql_select_db("$db_name", $db) or die ("DB not found");

$result = mysql_query("SELECT image_id FROM `$table` WHERE image_name='$i'");

$row = mysql_fetch_array($result);

$id = $row['image_id'];

header("Location: ".$url."/video".$id.".htm");
}
else
{
header("Location: ".$url."");
}
?>

Die URL zu dem Bild sieht so aus: image-fggf-3.htm

Aber wie mache ich das, dass er die Image_id und den image_name ausgibt?

Ich habe das so versucht:

<?
// Settings
///////////////////////////////////////////

$url = "http://www.anitube.de";
$table = "4images_images"; //do not edit if you have not changed table prefix 

// Code
///////////////////////////////////////////

include "config.php";
$a_url = $_SERVER["REQUEST_URI"];
$i = explode("/", $a_url);
$b = count($i);
$b = $b-1;
$i = str_replace(array("%20"), " ", $i[$b]);
if (($i != "") and ($i != "guest"))
{

$db = mysql_connect("$db_host", "$db_user", "$db_password") or die ("Error");

@mysql_select_db("$db_name", $db) or die ("DB not found");

$result = mysql_query("SELECT image_id FROM `$table` WHERE image_name='$i'");

$resultname = mysql_query("SELECT image_name FROM `$table` WHERE image_id='$i'");

$row = mysql_fetch_array($result);

$id = $row['image_id'];

$name = $row['image_name'];

header("Location: ".$url."/video-".$name."-".$id.".htm");
}
else
{
header("Location: ".$url."");
}
?>

Das scheint aber nicht richtig zu sein, da es dann nun so aufgerufen wird: image--3.htm
Der name zwischen - und - fehlt, dennoch wird es aufgerufen, aber wie klappt das richtig?